95 % confidence interval of two cardiac drugs x and y is as follows:
X= 2.2 - 3.5 and cardiac index 2.7 L/ m cube
Y= .6 - 1.6 and cardiac index 1.3 L/m cube
A test of significance is done to get a p value of .1
What's the likelihood that the the difference between cardiac index of X and Y is just by chance ?
So can you please tell us what is your source of the questions. I am not opening your threads because am thinking they are NBME, but if you tell us the source we'll be relieved
95 % confidence interval of two cardiac drugs x and y is as follows:
X= 2.2 - 3.5 and cardiac index 2.7 L/ m cube
Y= .6 - 1.6 and cardiac index 1.3 L/m cube
A test of significance is done to get a p value of .1
What's the likelihood that the the difference between cardiac index of X and Y is just by chance ?
its B....coz p value is 0.1,,,,,null hypothesis cant be rejected...in reality there is no difference..but given data suggest that 95% probability that both group have difference...so all 95% confidence is by chance....very low power study and high bete error...here beta error is 95%..
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