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  #1  
Old 08-08-2011
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Default measure it

A 75-year-old man is admitted to the ICU after aortic valve surgery. A pulmonary artery catheter yields the following data: central venous pressure (CVP) 5 mmHg, cardiac output (CO) 4.0 L/min, mean arterial pressure (MAP) 80 mmHg, mean pulmonary artery pressure (PAP) 26 mmHG, pulmonary artery occlusion pressure (PAOP) 10 mm Hg, and heart rate of 80. What is this personís pulmonary vascular resistance (PVR)?
A. 320 dynes-sec/cm5
B. 410 dynes-sec/cm5
C. 220 dynes-sec/cm5
D. 40 dynes-sec/cm5
E. 160 dynes-sec/cm5
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  #2  
Old 08-08-2011
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is it A? from
MAP=CO x TPR
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Old 08-08-2011
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D.40
Have not seen this type of quest
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  #4  
Old 08-08-2011
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Quote:
Originally Posted by ricko335 View Post
A 75-year-old man is admitted to the ICU after aortic valve surgery. A pulmonary artery catheter yields the following data: central venous pressure (CVP) 5 mmHg, cardiac output (CO) 4.0 L/min, mean arterial pressure (MAP) 80 mmHg, mean pulmonary artery pressure (PAP) 26 mmHG, pulmonary artery occlusion pressure (PAOP) 10 mm Hg, and heart rate of 80. What is this personís pulmonary vascular resistance (PVR)?
A. 320 dynes-sec/cm5
B. 410 dynes-sec/cm5
C. 220 dynes-sec/cm5
D. 40 dynes-sec/cm5
E. 160 dynes-sec/cm5
its B. 320 dynes-sec/cm5

normally we measure pressure in mmhg/l/min but if its given in dynes-sec/cm5...u just hv to multiply mmhg/l/min value with 80...

here R=P1-P2/Q
=26-10/4
=16/4
=4 mmhg/l/min...
now multiply with 80...
then its 320 dynes-sec/cm5...
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  #5  
Old 08-09-2011
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The correct answer is A.
PVR = (PAP mean - PAOP) / (CO ) x 80
= (26-10) / 4 x 80 = 320 dynes-sec/cm5

The normal range for PVR is 50 - 150 dynes-sec/cm5.
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