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Old 10-09-2011
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Default biochem question..if anyone could explain please!

consider a reaction that can be catalyzed by enzymes A with following kinetics


KM:5 into 10-6M

Vmax (mmol/min) :
20


at concentration of 5 into 10-4M SUBSTRATE ,THE VELOCITY OF REACTION catalyzed by enzyme A will be


A. 10
B.20
C.15


part 2 : at the concentration of 5 into 10-6 M substrate ,the velocity of reaction catalyzed by enzyme A will be
A. 10
B. 15
C. 20

Last edited by sibb; 10-09-2011 at 07:51 PM.
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  #2  
Old 10-09-2011
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What is the original question? not sure what you mean by "5 into 10-6M"?
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Old 10-09-2011
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it is the original question ...its a substrate concentration ...i dont know how to write it here ...........5 multiply by 10^-6 M is km for the enzyme !
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Old 10-10-2011
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Default ???

anyone??????????????????????
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  #5  
Old 10-10-2011
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The explanation is there with the kaplan question if u notice in ans section.
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