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  #1  
Old 02-28-2012
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Arrow NBME 3 Block 1 discussion

Q4:
I picked B...why A???

Q8:
does pernicious anemia also cause low platelets???

Q9:
Answer is C. Jak/stat kinases are also tyrosine kinases but for growth factors which is why they have a special name.

Q17:
I suck at biostats, I just hate these questions. I have no idea how to even begin solving this one. how do you calculate it??

Q36:
I picked E, but now I can see why it can be A...what did you pick??
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  #2  
Old 02-29-2012
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hi Haga , can u please send me offlines of NBME 3 , as i dont have it
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Old 02-29-2012
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Quote:
Originally Posted by rose View Post
hi Haga , can u please send me offlines of NBME 3 , as i dont have it
sent.......
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  #4  
Old 02-29-2012
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hey!
could i have them too? please
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Old 02-29-2012
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Qs 4 .... its A .. becoz rbcs swell so the conc outside is lower than rbcs which is 300 normally .. so here your ans is a conc less than 300 ..

as you convert 150 mM to 300osmol , ans A has 150 osmol which will cause rbc to swell while ans B is just 300 osmol whichis normal and so will have no fluid movement ....

Qs 8 ... well 85,000 is near the lower range of 1,00,000 to 3,00,000 so its not that low and may be no vit b12 so less dna formation so decrease in all cell line has begun as wbc also 4800 lower side of normal

Qs 9 see FA pg 294 .... growth factors at have MAP kinase and GH and prolactin have JAK stat ...

Qs 17 we all do but here its simple if you that the probability that a experiment result is due to chance is P , so if P is 0.1 the probability is 10 % ... see FA pg 54 ... same example is given saying if the chance is 5 % the P is 0.05

Qs 36 yes even i picked E but realized its A as abdominal aorta is retroperitoneal not ascending ......

help me with 15 , 32 , 25

in 32 how did you differentiate between chronic bronchitis and emphysema ??
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Quote:
Originally Posted by Hitman View Post
Qs 9 see FA pg 294 .... growth factors at have MAP kinase and GH and prolactin have JAK stat ...
I have 2010 FA. Can't correlate the same page number. So what is the answer???
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Quote:
Originally Posted by Hitman View Post
help me with 15 , 32 , 25

in 32 how did you differentiate between chronic bronchitis and emphysema ??
Q15:
Basically they are testing whether you know if the donor and recipient have to be a similar match. You can rule out females right away as they have XX, and the XY graft has a Y chromosome which will cause rejection. Now within the males the best combination would be the similar genetics as the donor, which is D. Best fit to not have rejection as the 2 genetics match.

Q25:
Points to subthalamic N. Part of basal ganglia (ie. striatum), so neuronal loss would lead to disinhibition in striatum (hemiballismus).

Q32:
Patient is young. Also has family history of lung disease at a young age. Best fit is a1-antitrypsin deficiency which would be E. No mention of cough or sputum either. Family history is the clincher.


Hey have also put up block 2 as well...so whenever you get the chance.
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It is tyrosine kinase receptor..... F .... see in endocrinology ... theres a table on it .....
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just doing block 2 ..... will be back in a few minutes ....
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Quote:
Originally Posted by Hitman View Post
It is tyrosine kinase receptor..... F .... see in endocrinology ... theres a table on it .....
they also have prolactin and GH under tyrosine kinase as well but these are Jak/stat?????
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growth factors are intrinsic tyrosine kinase ie MAP

prolactin and GH is receptor associated tyrosine kinase ie JAK/STAT pathway
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hi hitman could you send me the nbme3? thx
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Old 03-02-2012
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In Q12 the addition of two organism together result in growth of both organism which points towars plasmid transfering antibiotic resistance by conjugation but can some one explain me why the addition DNAse leads to death of both organism although the the cell wall is resistant to its entry so in no way it can inside the wall during conjugation to destroy the DNA???It made me think of Transduction in which dna can be destroyed by DNAse as stated can some one explain the above hw DNAse acting??

Also in Q21 what is the area damaged to cause hil loss of consciousness??

Last edited by mohitkmc; 03-02-2012 at 03:09 AM.
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Old 03-02-2012
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In q 33 why it cant be lipoxygenase 5 since they are talking about selective inhibition of enzyme?
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Quote:
Originally Posted by mohitkmc View Post
In Q12 the addition of two organism together result in growth of both organism which points towars plasmid transfering antibiotic resistance by conjugation but can some one explain me why the addition DNAse leads to death of both organism although the the cell wall is resistant to its entry so in no way it can inside the wall during conjugation to destroy the DNA???It made me think of Transduction in which dna can be destroyed by DNAse as stated can some one explain the above hw DNAse acting??
You are correct that it is via plasmid transfer through conjugation. Conjugation occurs via plasmid through a pilus. This is still inside the cell so the DNAse cannot reach it....hence it is not occuring through conjugation. Has nothing to do with transduction, no mention of bacteriophage.

Only way the DNAse works is if the transfer is via transformation. Release of free DNA by both bacteria outside the cell which the DNAse can break down.


Quote:
Originally Posted by mohitkmc View Post
Also in Q21 what is the area damaged to cause hil loss of consciousness??
It is what is referred in the stem....ventral tegmentum of midbrain. The reticular formation is responsible for alertness and sleep/waking cycles. It's descruction will lead to unconciusness and even coma if extensive enough.


Quote:
Originally Posted by mohitkmc View Post
In q 33 why it cant be lipoxygenase 5 since they are talking about selective inhibition of enzyme?
That is the answer. D. They are asking about 5-lipoxygenase.
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Old 03-03-2012
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Quote:
Originally Posted by haga View Post
You are correct that it is via plasmid transfer through conjugation. Conjugation occurs via plasmid through a pilus. This is still inside the cell so the DNAse cannot reach it....hence it is not occuring through conjugation. Has nothing to do with transduction, no mention of bacteriophage.

Only way the DNAse works is if the transfer is via transformation. Release of free DNA by both bacteria outside the cell which the DNAse can break down.




It is what is referred in the stem....ventral tegmentum of midbrain. The reticular formation is responsible for alertness and sleep/waking cycles. It's descruction will lead to unconciusness and even coma if extensive enough.




That is the answer. D. They are asking about 5-lipoxygenase.
In q 12 they have nt mentioned abt bacteriophage bt in it if it was transformation then there should have beed death of one bacteria leading to survival of the other to both antibiotics but in question stem they mention that both the types acquired the resistance to infection and both survived so thats why I think better option will be Transduction even though they have not mentioned abt bacteriophage bt we have to assume that because I cant understand hw in transformation both of them survived and acquired resistance together???
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Quote:
Originally Posted by mohitkmc View Post
In q 12 they have nt mentioned abt bacteriophage bt in it if it was transformation then there should have beed death of one bacteria leading to survival of the other to both antibiotics but in question stem they mention that both the types acquired the resistance to infection and both survived so thats why I think better option will be Transduction even though they have not mentioned abt bacteriophage bt we have to assume that because I cant understand hw in transformation both of them survived and acquired resistance together???
How will a DNAse by itself get through a viral capsid. DNAase can only break down free DNA, not get through a capsid or an envelope.

When co-cultured, there are always some bacteria dying (normal part of life cycle, growth and death) and thus spilling their cellular contents into the medium and bacteria have this tendency to pick up extraneous pieces of DNA from the medium. This is what is happening.

Answer is D.
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