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  #1  
Old 03-02-2012
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Default Weight calculation

A 70-kg (154-lb) man on a fixed NaCl intake
(200 mmol/day) is given daily injections of a
potent mineralocorticoid hormone for 4 days. He
has free access to water and consumes his usual
caloric intake. Excretion of NaCl is as follows:
Day NaCl (mmol)
1 30
2 90
3 180
4 200
Assuming that 1 L of 0.9% saline contains 150
mmol of NaCl and weighs 1 kg, how much will
this patient weigh (in kg) at the end of day 4?
(A) 66
(B) 68
(C) 70
(D) 72
(E) 74
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  #2  
Old 03-02-2012
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D) 72


200x4 = 800 --- total intake in 4 days

total clearence is 30+90+180+200 = 500

800 - 500 = 300

300/150 = 2kg
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Quote:
Originally Posted by DocSikorski View Post
D) 72


200x4 = 800 --- total intake in 4 days

total clearence is 30+90+180+200 = 500

800 - 500 = 300

300/150 = 2kg
thanks alot , I had no idea how to solve this but u added the 2 to his original wt .???
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Old 03-02-2012
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Quote:
Originally Posted by DocSikorski View Post
D) 72


200x4 = 800 --- total intake in 4 days

total clearence is 30+90+180+200 = 500

800 - 500 = 300

300/150 = 2kg
Stupid question here, but would you not lose 2 lbs so 68?
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Quote:
Originally Posted by gear2d View Post
Stupid question here, but would you not lose 2 lbs so 68?
NaCl would drag the water with it. (he has access to water)By the same deal as Aldosterone causes hypertension
So you pump the guy up! =)
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Old 03-02-2012
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Quote:
Originally Posted by DocSikorski View Post
NaCl would drag the water with it. (he has access to water)By the same deal as Aldosterone causes hypertension
So you pump the guy up! =)
I must be out of it. You are correct. I kept thing excretion and forgot that of that 800 that 300 was still in him.
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