USMLE Forums banner

95% Confidence Interval

9K views 3 replies 3 participants last post by  just_md 
#1 ·
A study is conducted to evaluate intelligence quotient (IQ) scores for patients with various types of schizophrenia. Twenty patients were dropped from the sample because they could not complete two or more portions of the test. Four additional patients refused to take the test. Results for the 100 patients who completed the test showed an average IQ of 110 with a standard deviation of 20. Which of the following is the best estimate of the 95% confidence interval for this sample?
A. 70 to 130
B. 70 to 150
C. 85 to 115
D. 90 to 130
E. 105 to 115
F. 106 to 114
 
#4 ·
Choice F is correct

The formula for the confidence interval of the mean (CI) is: CI = ± Z x SD*s/ n
The mean is given as 110. To achieve a 95% confidence interval use a Z-score of 1.96 (or 2.0. to make the calculation easier). The standard deviation (SD) is given as 20 and the sample size is given as 100 Inserting these values into the formula: CI = 110 ± 4 or a range of 106 to 114.

khushboo you are right.
 
This is an older thread, you may not receive a response, and could be reviving an old thread. Please consider creating a new thread.
Top