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  #1  
Old 06-23-2010
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Stats 95% of observations

A large study of serum folate levels in women aged 16 - 45years reveals that this parameter is normally distributed, with a mean of 5.0 ng/ml and a standard deviation of 0.5 ng/ml. According to the study results, 95% of serum folate observations in these patients will lie between the following limits.

A- 4.0 and 6.0 ng/ml
B- 4.0 and 5.5 ng/ml
C- 4.5 and 5.5 ng/ml
D- 3.5 and 6.0 ng/ml
E- 3.5 and 6.5 ng/ml
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  #2  
Old 06-23-2010
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Default A

The correct answer is A- 4.0 and 6.0 ng/ml...

1SD is .5 ng/ml....so 2SD = 1 ng/ml....
95% CI = mean +/- 2SD....so....5 +/- 1 = 4 - 6 ng/ml....
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Old 06-23-2010
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Arrow Correct .. but

Quote:
Originally Posted by khushboo View Post
The correct answer is A- 4.0 and 6.0 ng/ml...

1SD is .5 ng/ml....so 2SD = 1 ng/ml....
95% CI = mean +/- 2SD....so....5 +/- 1 = 4 - 6 ng/ml....
Your answer is correct. But they don't call it Confidence Interval. This is just 95% of a normally distributed population. Which is as you said mean +/- 2 standard deviations, 95% Confidence Interval of the mean on the other hand is calculated by this formula
mean +/- 2 Z scores X SD/N
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Old 06-23-2010
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Default

1 sd - 68
2 sd - 95
3sd - 99.7

so here its 95..ie 2sd...so 1 on each side of 5

which will be 5-1= 4
and 5+1=6
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Old 06-24-2010
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You are all correct the ans is A. thanks for the explanations. I was actually confused and didn't know how to go about it. my fear has always been biostatistics but i thank God for this forum. the forum is actually helping me get thru it .thanks again
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Old 08-22-2011
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Quote:
Originally Posted by rasheed View Post
Your answer is correct. But they don't call it Confidence Interval. This is just 95% of a normally distributed population. Which is as you said mean +/- 2 standard deviations, 95% Confidence Interval of the mean on the other hand is calculated by this formula
mean +/- 2 Z scores X SD/N
Actually, the formula for a 95% CI is

mean + or - [Z score x sd/sqrt(N)]...and Z is almost 2 (95% confidence Z score = 1.96)...so, you dont have to multiple Z score by two...and dont forget the square root in the denominator.
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Old 08-22-2011
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Hi bebix..
Can you please explain me what value should we take for 'N'..??
Because here they are saying large sample??..
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Old 08-22-2011
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Quote:
Originally Posted by struggle View Post
Hi bebix..
Can you please explain me what value should we take for 'N'..??
Because here they are saying large sample??..
Oh yeah i got it..I didnt looked the question properly..they are asking for 95% population..
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