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Old 06-28-2012
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DNA Number of ATP/GTP in Translation

Is the following correct?

(a)In first translation cycle: 1atp(AA activation) + [2atp + 1gtp] (initiation) + 2gtp(elongation) +1gtp(termination)

(b)For each AA translated following methionine: 1atp(AAactivation) + 1gtp(initiation) + 3gtp(elongation & termination)

Doubt: But the one gtp in initiation is the gtp attached to eIF2 which is hydrolysed to form assoc b/w 60S and 40S to form 80S. why is this taken in(b) then?
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Default Source

http://www.prep4usmle.com/forum/thread/51650/
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Old 06-28-2012
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Warning!

no idea... just one Q... do we have to know this ????
:sorry::sorry:
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Quote:
Originally Posted by tarsuc View Post
Is the following correct?

(a)In first translation cycle: 1atp(AA activation) + [2atp + 1gtp] (initiation) + 2gtp(elongation) +1gtp(termination)

(b)For each AA translated following methionine: 1atp(AAactivation) + 1gtp(initiation) + 3gtp(elongation & termination)

Doubt: But the one gtp in initiation is the gtp attached to eIF2 which is hydrolysed to form assoc b/w 60S and 40S to form 80S. why is this taken in(b) then?
In (b) i agree with you that that there should not be "1gtp(initiation)"

but in (a) can you please tell me what is the purpose of" 2atp in the initiation" process??????
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Default copy pasted (not sure if correct)

- Initiation has some steps. First 40s & 60s are separated & eIFs (3 & 1A) bind to 40s to delay its reassociation with 60s.

- (GTP-eIF2 + Met-tRNA) bind with 40s & form 43s preinitiation complex.

- mRNA will be activated which needs 1 ATP (ATP---> ADP + P).

- 43s preinitiation binds with mRNA & they form 48s initiation complex, & 1 ATP is used again (ATP---> ADP + P).

- 48s init. finds the start codon (AUG).

- GTP bound to eIF2 will be hydrolized---> GDP-eIF2 + P. This reaction causes the release of eIF3 & eIF1A from 48s init. complex ---> rapid association of 60s with 40s & thus forming 80s initiation complex.

So for initiation phase we have 2 ATP + 1 GTP
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Quote:
Originally Posted by tarsuc View Post
- Initiation has some steps. First 40s & 60s are separated & eIFs (3 & 1A) bind to 40s to delay its reassociation with 60s.

- (GTP-eIF2 + Met-tRNA) bind with 40s & form 43s preinitiation complex.

- mRNA will be activated which needs 1 ATP (ATP---> ADP + P).

- 43s preinitiation binds with mRNA & they form 48s initiation complex, & 1 ATP is used again (ATP---> ADP + P).

- 48s init. finds the start codon (AUG).

- GTP bound to eIF2 will be hydrolized---> GDP-eIF2 + P. This reaction causes the release of eIF3 & eIF1A from 48s init. complex ---> rapid association of 60s with 40s & thus forming 80s initiation complex.

So for initiation phase we have 2 ATP + 1 GTP
i can not confirm/verify the source of above info but for boards i think following info should be sufficient:

"In process of translation we are consuming 1ATP (for activation),1GTP(in initiation),2GTPs(in elongation)and 1GTP(in termination)
So IN ALL 6 high energy bonds are consumed in each translation cycle"

AND elongation consumes 4high energy bonds(2 bonds from 2GTP molecules,2 bonds from ATP molecule which was initially captured in activation process and now used by peptidy transferase in peptide bond formation)
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Quote:
Originally Posted by tarsuc View Post
2 bonds from atp and 1 from rest u mean?
Exactly; 2high energy bonds from ATP as it converts to AMP and 1 high energy bond coming from GTP molecule
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