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#1
08-05-2012
 USMLE Forums Master Steps History: 1+CK+CS Posts: 1,867 Threads: 149 Thanked 2,107 Times in 1,049 Posts Reputation: 2127
The specificity of the test is

The data presented below compares the results of a diagnostic test in the presence and absence of a disease.

................................Disease present........................Disease absent

Positive test.........................40................... ......................5

Negative test.......................10..................... ...................95

Total...................................50........ ..............................100

The specificity of the test is

A. 0.05

B. 0.40

C. 0.80

D. 0.90

E. 0.95

#2
08-05-2012
 USMLE Forums Master Steps History: 1+CK+CS+3 Posts: 730 Threads: 90 Thanked 460 Times in 289 Posts Reputation: 470

Quote:
 Originally Posted by Novobiocin The data presented below compares the results of a diagnostic test in the presence and absence of a disease. ................................Disease present........................Disease absent Positive test.........................40................... ......................5 Negative test.......................10..................... ...................95 Total...................................50........ ..............................100 The specificity of the test is A. 0.05 B. 0.40 C. 0.80 D. 0.90 E. 0.95

E......................................
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#3
08-05-2012
 USMLE Forums Master Steps History: 1+CK+CS Posts: 1,867 Threads: 149 Thanked 2,107 Times in 1,049 Posts Reputation: 2127

Explanation:

The correct answer is E. Specificity is the proportion of persons without the disease who are correctly identified
by the test as being disease-free. It is given by TN/(FP + TN), where TN stands for true negatives (people who
do not have the disease and test negative on the test) and FP stands for false positives (people who do not
have the disease but test positive on the test). In this case, 95/(5 + 95) = 95/100 = 0.95.

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