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thx!!

i didnt apply this rule. i just calculated the odds of a second child having cleft lip and ignored the fact whether it could be AR or AD.

luckily for ur question, i know a little bit more than i did yesterday.:)
 

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where is it given?
i dont understand how its decide not AR or AD in question.:toosad::notsure:
i think the question wants us to decide for ourselves whether or not it is AR or AD. if its AR, then DZ rate will be 25% of MZ. if it were AD, then it would be 50% of MZ. n if these rules applied, u apply one famous formula:
concordance rate = (MZ - DZ)/(100 - DZ)

then if he is having second child, u times the results u get twice (ie: 0.5 x 0.5 = 0.25 = 25%)

but thats not the case here. it's neither AR nor AD. so we have to decide that its more than the population n less than MZ n based on that information alone, pick an answer.

am i making any sense?:eek:
 
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