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reply....for hardy-weinbeg equation

....hey!p2 is taken for homozygous....i.e:complete homozygous n dominant traits....n q2 for homogyous recessive...n 2pq for heterozygous individuals......if the frequency is given u can find out the total population....n if the population is given u can find out the frequency of the homozygous [dominant or recessive]and heterozygous populations.....hope now u can solve the problems....if u still hav doubt u can mail me a question to my gmail account....ill solve that n ll send u...all the best for u r exam.....bye...
 
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