[Hope2Pass]

Question:

A gene encodes a protein with 150 amino acids. There is one intron of 1,000 bps , a region of 5' UTR of 100 bp, and a 3' UTR of 200 bp. In the final processed mRNA, how many bases lie between the start AUG codon and the final termination codon ?

A) 1,750
B) 750
C) 650
D) 450
E) 150

Answer: ? (Please provide an explanation for how you reached your answer)

 

[drahmednawaz]

Answer is D.

A single amino acid is coded by three base pairs. A protein with 150 amino acids must have 150 * 3 = 450 base pairs.

In the final processed mRNA, introns are spliced out ( removed ); we have only exons.

 

[Myticketout]

D. Because each amino acid is encoded by 3 bases. so 150x3=450. You do not include UTR and introns ecause they are not translated.

 

[Hope2Pass]

D

Yes D is the correct answer!

 

[rsin21]

but total bases In the final processed mRNA it will be 5UTR + 3UTR + 3x150

= 750 (plus poly A tail ,not given here)


click image to enlarge

 

[drahmednawaz]

but total bases In the final processed mRNA it will be 5UTR + 3UTR + 3x150

= 750 (plus poly A tail ,not given here)

The Q is asking about base pairs between stop and start codons. That doesn't include 5'UTR, 3'UTR, or poly A tail. Count between AUG (start codon) and UAG (stop codon).

 

[rsin21]

The Q is asking about base pairs between stop and start codons. That doesn't include 5'UTR, 3'UTR, or poly A tail. Count between AUG (start codon) and UAG (stop codon).

I know that....just making it clear if the question asked just for final mRNA

thanks nyways

 

[multialisafe]

i believe it's ( d )