A. 1% of the time

B. 5% of the time

C. 13% of the time

D. 20% of the time

E. 40% of the time

1 - 5 of 5 Posts

A. 1% of the time

B. 5% of the time

C. 13% of the time

D. 20% of the time

E. 40% of the time

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·
590 Posts

My guess is C. 13% of the time

Chance that a Y will come with a Z (.5) * chance that an X will come with that Y (.25)

.25 * .50 = .125 ≈ 13%

Im not sure how to answer this question

but i was thinking along the lines of

(0.25+0.50) - (0.25*0.50) which equals 62.5

this gives probability of not mutually exclusive events.

Not sure, im waiting for the answer and an explanation!

Joined

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590 Posts

:notsure:Im not sure how to answer this question

but i was thinking along the lines of

(0.25+0.50) - (0.25*0.50) which equals 62.5

this gives probability of not mutually exclusive events.

Not sure, im waiting for the answer and an explanation!

Doesn't that give the probability of one of two events happening or both (genes transferred ∈ {x,y} ∪ {y,z} ∪ {x,y,z})?

The events for which the probabilities are given aren't mutually exclusive; however, they are also not separate, since x, y, and z are on the same chromosome. {x,y,z} is the only set that could include both x and z.

I was thinking of the probabilities as approximating synteny; that is to say, since y and z together is twice as probable as x and y, then y and z must be about half the distance apart:

------x------y---z----------

So the probability that the whole string would be transferred would approximate the probability of the x-z synteny, which would be the

Very good.My guess is C. 13% of the time

Chance that a Y will come with a Z (.5) * chance that an X will come with that Y (.25)

.25 * .50 = .125 ≈ 13%

Correct Ans is C) 13%

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