Step 1 practice Qnz - 10
A 45 y/o woman is hospitalized after an automobile accident. The physician collects 1.44L of urine from the patient in a 24hr period. The clinical lab returns the following result.
Plasma creatinine con : 2.0 mg/ml
Plasma urea con : 15 umol/ml
Urine creatinine con : 100 mg/ml
Urine urea con : 160 umol/ml
What is the approx glomerular filtration Rate (GFR) in ml/min of this patient?
I think 50. I did it like this:
1.44L/24h is equivalent at 1440ml/24h wich is equivalent at 60ml/h wich is the same as saying 1ml/min. That's the V (urine flow).
Then you do the formula of Clearance of creatinine.
Cl: VxUrine concentration of creatinine
Plasma concentration of creatinie
Answer is 50.
Any one.... !!! come on guy...
C is the answer!
The answer is C (50)
I hope it did help you. Good luck:happy::happy::happy:
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