95 % confidence interval of two cardiac drugs x and y is as follows:
X= 2.2 - 3.5 and cardiac index 2.7 L/ m cube
Y= .6 - 1.6 and cardiac index 1.3 L/m cube
A test of significance is done to get a p value of .1
What's the likelihood that the the difference between cardiac index of X and Y is just by chance ?
a-0%
b-95%
c-97.5%
d-66.5%
X= 2.2 - 3.5 and cardiac index 2.7 L/ m cube
Y= .6 - 1.6 and cardiac index 1.3 L/m cube
A test of significance is done to get a p value of .1
What's the likelihood that the the difference between cardiac index of X and Y is just by chance ?
a-0%
b-95%
c-97.5%
d-66.5%